Integrand size = 22, antiderivative size = 106 \[ \int \csc ^2(a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx=\frac {2 \operatorname {EllipticF}\left (a-\frac {\pi }{4}+b x,2\right )}{3 b}-\frac {2 \cos (2 a+2 b x) \sqrt {\sin (2 a+2 b x)}}{3 b}-\frac {2 \cos (2 a+2 b x) \sin ^{\frac {5}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^2(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x)}{5 b} \]
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Time = 0.07 (sec) , antiderivative size = 106, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {4385, 2715, 2720} \[ \int \csc ^2(a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx=\frac {2 \operatorname {EllipticF}\left (a+b x-\frac {\pi }{4},2\right )}{3 b}-\frac {2 \sin ^{\frac {5}{2}}(2 a+2 b x) \cos (2 a+2 b x)}{5 b}-\frac {2 \sqrt {\sin (2 a+2 b x)} \cos (2 a+2 b x)}{3 b}+\frac {\sin ^{\frac {9}{2}}(2 a+2 b x) \csc ^2(a+b x)}{5 b} \]
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Rule 2715
Rule 2720
Rule 4385
Rubi steps \begin{align*} \text {integral}& = \frac {\csc ^2(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x)}{5 b}+\frac {14}{5} \int \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx \\ & = -\frac {2 \cos (2 a+2 b x) \sin ^{\frac {5}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^2(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x)}{5 b}+2 \int \sin ^{\frac {3}{2}}(2 a+2 b x) \, dx \\ & = -\frac {2 \cos (2 a+2 b x) \sqrt {\sin (2 a+2 b x)}}{3 b}-\frac {2 \cos (2 a+2 b x) \sin ^{\frac {5}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^2(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x)}{5 b}+\frac {2}{3} \int \frac {1}{\sqrt {\sin (2 a+2 b x)}} \, dx \\ & = \frac {2 \operatorname {EllipticF}\left (a-\frac {\pi }{4}+b x,2\right )}{3 b}-\frac {2 \cos (2 a+2 b x) \sqrt {\sin (2 a+2 b x)}}{3 b}-\frac {2 \cos (2 a+2 b x) \sin ^{\frac {5}{2}}(2 a+2 b x)}{5 b}+\frac {\csc ^2(a+b x) \sin ^{\frac {9}{2}}(2 a+2 b x)}{5 b} \\ \end{align*}
Time = 0.51 (sec) , antiderivative size = 76, normalized size of antiderivative = 0.72 \[ \int \csc ^2(a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx=\frac {20 \operatorname {EllipticF}\left (a-\frac {\pi }{4}+b x,2\right ) \sqrt {\sin (2 (a+b x))}+9 \sin (2 (a+b x))-10 \sin (4 (a+b x))-3 \sin (6 (a+b x))}{30 b \sqrt {\sin (2 (a+b x))}} \]
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Time = 20.80 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.31
method | result | size |
default | \(\frac {4 \sqrt {2}\, \left (\frac {\sqrt {2}\, \sin \left (2 x b +2 a \right )^{\frac {5}{2}}}{20}+\frac {\sqrt {2}\, \left (\sqrt {\sin \left (2 x b +2 a \right )+1}\, \sqrt {-2 \sin \left (2 x b +2 a \right )+2}\, \sqrt {-\sin \left (2 x b +2 a \right )}\, \operatorname {EllipticF}\left (\sqrt {\sin \left (2 x b +2 a \right )+1}, \frac {\sqrt {2}}{2}\right )+2 \sin \left (2 x b +2 a \right )^{3}-2 \sin \left (2 x b +2 a \right )\right )}{24 \cos \left (2 x b +2 a \right ) \sqrt {\sin \left (2 x b +2 a \right )}}\right )}{b}\) | \(139\) |
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\[ \int \csc ^2(a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx=\int { \csc \left (b x + a\right )^{2} \sin \left (2 \, b x + 2 \, a\right )^{\frac {7}{2}} \,d x } \]
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Timed out. \[ \int \csc ^2(a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx=\text {Timed out} \]
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\[ \int \csc ^2(a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx=\int { \csc \left (b x + a\right )^{2} \sin \left (2 \, b x + 2 \, a\right )^{\frac {7}{2}} \,d x } \]
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\[ \int \csc ^2(a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx=\int { \csc \left (b x + a\right )^{2} \sin \left (2 \, b x + 2 \, a\right )^{\frac {7}{2}} \,d x } \]
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Timed out. \[ \int \csc ^2(a+b x) \sin ^{\frac {7}{2}}(2 a+2 b x) \, dx=\int \frac {{\sin \left (2\,a+2\,b\,x\right )}^{7/2}}{{\sin \left (a+b\,x\right )}^2} \,d x \]
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